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x^2+5.75x+2.5=0
a = 1; b = 5.75; c = +2.5;
Δ = b2-4ac
Δ = 5.752-4·1·2.5
Δ = 23.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.75)-\sqrt{23.0625}}{2*1}=\frac{-5.75-\sqrt{23.0625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.75)+\sqrt{23.0625}}{2*1}=\frac{-5.75+\sqrt{23.0625}}{2} $
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